Problem: a. Given that Ka for HClO is 4.0 × 10-8 at 25°C, what is the value of Kb for ClO– at 25°C? b. Given that Kb for CH3CH2NH2 is 6.3 × 10-4 at 25°C, what is the value of Ka for CH3CH2NH3+ at 25°C?

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a. Given that Ka for HClO is 4.0 × 10-8 at 25°C, what is the value of Kb for ClO at 25°C? 




b. Given that Kb for CH3CH2NH2 is 6.3 × 10-4 at 25°C, what is the value of Ka for CH3CH2NH3+ at 25°C?

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Based on our data, we think this problem is relevant for Professor Sevian's class at University of Massachusetts Boston.