cathode → reduction → oxidation number decreases
anode → oxidation → oxidation number increases
For ions: charge of the ion = oxidation number
For neutral atoms/compound: oxidation number = 0
Calculate Eocell for the following balanced redox reaction.
Br2(l) + 2I−(aq) → 2Br−(aq) + I2(s)
Express your answer using two significant figures.
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