For this problem, we are asked for the Ka2 expression so we don't actually need to compute anything. We just have to set it up.
Know that H2CO3 (Carbonic acid) is a polyprotic acid which means we have more than 1 acidic hydrogen that can dissociate. In this specific acid, we have 2 acidic hydrogens. Shown below is the form of carbonic acid for every step that it losses each hydrogen. We also have the proper Ka's that we will use for each removal of hydrogen. Since we are asked for Ka2 we focus on the highlighted step and we start with the intermediate form in the center.
Complete the Ka2 expression for H2CO3 in an aqueous solution. Ka2 = 4.69 x 10-11
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Diprotic Acid concept. You can view video lessons to learn Diprotic Acid. Or if you need more Diprotic Acid practice, you can also practice Diprotic Acid practice problems.
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Our tutors rated the difficulty ofComplete the Ka2 expression for H2CO3 in an aqueous solution...as medium difficulty.
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Our expert Chemistry tutor, Dasha took 3 minutes and 39 seconds to solve this problem. You can follow their steps in the video explanation above.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Hendrickson's class at UCB.