Ch.11 - Liquids, Solids & Intermolecular ForcesWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Which choice best describes the polarity of ICl 5?a. The molecule is polar and has polar bonds.b. The molecule is nonpolar and has polar bonds.c. The molecule is polar and has nonpolar bonds.d. The mo

Solution: Which choice best describes the polarity of ICl 5?a. The molecule is polar and has polar bonds.b. The molecule is nonpolar and has polar bonds.c. The molecule is polar and has nonpolar bonds.d. The mo

Problem

Which choice best describes the polarity of ICl 5?

a. The molecule is polar and has polar bonds.

b. The molecule is nonpolar and has polar bonds.

c. The molecule is polar and has nonpolar bonds.

d. The molecule is nonpolar and has nonpolar bonds.

Solution

For this problem, we need to do the following steps:

Step 1: Determine the central atom in this molecule.

Step 2: Calculate the total number of valence electrons present.

Step 3: Draw the Lewis structure for the molecule.

Step 4: Draw dipole arrows for each bond.

Step 5: Determine the polarity of the molecule.


Step 1: Iodine (EN = 2.5) is less electronegative than chlorine (EN = 3) so iodine is the central atom.


Step 2: The total number of valence electrons present in ICl5 is:


            Group             Valence Electrons

I           7A                   1 × 7 e7 e

Cl        7A                   5 × 7 e35 e

Total:  42 valence e


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