Ch.16 - Aqueous Equilibrium WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Write the balanced neutralization reaction between H2SO(sulfuric acid) and KOH (potassium hydroxide) in aqueous solution. Also find the concentration of sulfuric acid remaining after 0.150L of 0.470 M H2SO4 is mixed with 0.100L of 0.230 M KOH. 

Solution: Write the balanced neutralization reaction between H2SO4 (sulfuric acid) and KOH (potassium hydroxide) in aqueous solution. Also find the concentration of sulfuric acid remaining after 0.150L of 0.470

Problem

Write the balanced neutralization reaction between H2SO(sulfuric acid) and KOH (potassium hydroxide) in aqueous solution. Also find the concentration of sulfuric acid remaining after 0.150L of 0.470 M H2SO4 is mixed with 0.100L of 0.230 M KOH. 

Solution

We’re being asked to write the reaction equation between H2SO4 and KOH and find the concentration of H2SOafter some KOH is added to the solution.


Let’s first write the balanced reaction between H2SO4 and KOH:

Reactants:

2SO4

▪ oxyacid → 2 more oxygens than hydrogens → strong oxyacid
▪ a strong acid → will completely dissociate in solution
H2SO4(aq) → 2 H+(aq) + SO42-(aq) 

KOH

Solution BlurView Complete Written Solution