# Problem: Sodium bicarbonate reacts with hydrochloric acid in a gas-forming reaction to produce aqueous sodium chloride, water, and carbon dioxide gas:NaHCO3(s) + HCl(aq) → NaCl(aq) + H2O(l) + CO2(g)Determine the mass of CO2 gas produced when 8.67 g of NaHCO3 is added to a solution that contains 5.65 g of HCl.

###### FREE Expert Solution

Notice that we are given the mass of both reactants: this means we need to determine the limiting reactant, which is the reactant that forms the less amount of product

This is because once the limiting reactant is all used up, the reaction can no longer proceed and make more products.

This means the limiting reactant determines the maximum mass of the product (CO2) formed.

We need to perform a mole-to-mole comparison between each reactant and CO2.

Balanced Reaction: NaHCO3(s) + HCl(aq)  NaCl(aq) + H2O(l) + CO2(g)

For NaHCO3: From the balanced equation, 1 mole of NaHCO3 form 1 mole of CO2

The moles of CO2 formed by 8.67 g NaHCO3 is:

89% (455 ratings)
###### Problem Details

Sodium bicarbonate reacts with hydrochloric acid in a gas-forming reaction to produce aqueous sodium chloride, water, and carbon dioxide gas:

NaHCO3(s) + HCl(aq) → NaCl(aq) + H2O(l) + CO2(g)

Determine the mass of CO2 gas produced when 8.67 g of NaHCO3 is added to a solution that contains 5.65 g of HCl.