🤓 Based on our data, we think this question is relevant for Professor Jones' class at TEXAS.

MM of Cl_{2 }and PCl5 is 70.9 g/mol and 208.2 g/mol

$\mathrm{g}{\mathrm{PCl}}_{5}=3.5\overline{)\mathrm{g}{\mathrm{Cl}}_{2}}\left(\frac{1\overline{)\mathrm{mol}{\mathrm{Cl}}_{2}}}{70.9\overline{)\mathrm{g}{\mathrm{Cl}}_{2}}}\right)\left(\frac{2\overline{)\mathrm{mol}{\mathrm{PCl}}_{5}}}{5\overline{)\mathrm{mol}{\mathrm{Cl}}_{2}}}\right)\left(\frac{208.2\mathrm{g}{\mathrm{PCl}}_{5}}{1\overline{)\mathrm{mol}\hspace{0.17em}{\mathrm{PCl}}_{5}}}\right)$

The reaction of chlorine gas with solid phosphorus produces solid phosphorus pentachloride. How many grams of PCl_{5} are produced from 3.5 g of Cl _{2}?

5Cl_{2}(g) + 2P(s) → 2PCl(s)

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Stoichiometry concept. You can view video lessons to learn Stoichiometry. Or if you need more Stoichiometry practice, you can also practice Stoichiometry practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Jones' class at TEXAS.