Problem: The combustion of octane, C8H18, proceeds according to the reaction:2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(l)If 402 mol of octane combusts, what volume of carbon dioxide is produced at 14.0 °C and 0.995 atm?

FREE Expert Solution

Determine the moles of CO2 first

nCO2=402 mol C8H18(16 mol CO22 mol C8H18)=3216 mol CO2

Now we have the number of moles CO2 produced, we can now calculate its volume using the ideal gas equation:

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Problem Details

The combustion of octane, C8H18, proceeds according to the reaction:


2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(l)

If 402 mol of octane combusts, what volume of carbon dioxide is produced at 14.0 °C and 0.995 atm?

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