Bond Angles Video Lessons

Concept: VSEPR Model for Bonding

# Problem: What are the expected bond angles in ICl4+?a. 90°b. 109.5°c. 120°d. 180 °

###### FREE Expert Solution
83% (116 ratings)
###### FREE Expert Solution

We’re being asked to identify the bond angle in ICl4+. Since we don’t know the Lewis structure for ICl4+, we need to do the following steps:

Step 1: Determine the central atom in this molecule.

Step 2: Calculate the total number of valence electrons present.

Step 3: Draw the Lewis structure for the molecule.

Step 4: Determine the number of electron groups around the indicated atom.

Step 5: Determine the electron geometry and bond angle using this:

Electron Regions          Electronic Geometry          Bond Angles

2                                      linear                                    180˚

3                                      trigonal planar                      120˚

4                                      tetrahedral                            109.5˚

5                                      trigonal bipyramidal              90˚, 120˚, and 180˚

6                                      octahedral                            90˚ and 180˚

83% (116 ratings)
###### Problem Details

What are the expected bond angles in ICl4+?

a. 90°

b. 109.5°

c. 120°

d. 180 °

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Bond Angles concept. You can view video lessons to learn Bond Angles. Or if you need more Bond Angles practice, you can also practice Bond Angles practice problems.

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Our tutors rated the difficulty ofWhat are the expected bond angles in ICl4+?a. 90°b. 109.5°c....as medium difficulty.

How long does this problem take to solve?

Our expert Chemistry tutor, Dasha took 3 minutes and 52 seconds to solve this problem. You can follow their steps in the video explanation above.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Guerra's class at RUTGERS.