We’re being asked to calculate the actual yield of Mg(NO3)2 in the reaction if the efficiency (percent yield) is 30.60%.
The balanced chemical equation is:
Mg + Cu(NO3)2→ Mg(NO3)2 + Cu
Recall that percent yield is given by:
The theoretical yield is not given but we can use the given information: 140.2 g Mg reacts with excess Cu(NO3)2.
Assuming an efficiency of 30.60%, calculate the actual yield of magnesium nitrate formed from 140.2 g of magnesium and excess copper (II) nitrate.
Mg + Cu(NO3)2 → Mg(NO3)2 + Cu
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