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Solution: Combining 0.254 mol of Fe2O3 with excess carbon produced 12.8 g of Fe.Fe2O3 + 3C → 2Fe + 3COa) What is the actual yield of iron in moles?b)What was the theoretical yield of iron in moles?c)What was the percent yield?

Problem

Combining 0.254 mol of Fe2O3 with excess carbon produced 12.8 g of Fe.

Fe2O3 + 3C → 2Fe + 3CO

a) What is the actual yield of iron in moles?



b)What was the theoretical yield of iron in moles?


c)What was the percent yield?