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Problem: Combining 0.254 mol of Fe2O3 with excess carbon produced 12.8 g of Fe.Fe2O3 + 3C → 2Fe + 3COa) What is the actual yield of iron in moles?b)What was the theoretical yield of iron in moles?c)What was the percent yield?

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Combining 0.254 mol of Fe2O3 with excess carbon produced 12.8 g of Fe.

Fe2O3 + 3C → 2Fe + 3CO

a) What is the actual yield of iron in moles?



b)What was the theoretical yield of iron in moles?


c)What was the percent yield?

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