How many milliliters of a 9.0 M H _{2}SO_{4} solution are needed to make 0.45 L of a 3.5 M solution?

We are being asked to find how many milliliters of 9.0 M H_{2}SO_{4} is needed to make a 0.45 L of 3.5 M solution.

When we are **adding water (or solvent) to a solution** to decrease its concentration, we are **diluting **the solution.

When dealing with **dilution **we will use the following equation:

$\overline{){{\mathbf{M}}}_{{\mathbf{1}}}{{\mathbf{V}}}_{{\mathbf{1}}}{\mathbf{=}}{{\mathbf{M}}}_{{\mathbf{2}}}{{\mathbf{V}}}_{{\mathbf{2}}}}$

M_{1} = initial concentration

V_{1} = initial volume

M_{2} = final concentration

V_{2} = final volume

**Calculate the ****initial volume (milliliters needed) of the H _{2}SO_{4} solution.**