Ch.12 - SolutionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Choose the pair of substances that are most likely to form a homogeneous solution.a. C6H14 and C10H20b. LiBr and C5H12c. N2O4 and NH4Cld. C6H14 and H2Oe. None of these pairs will form a homogeneous so

Solution: Choose the pair of substances that are most likely to form a homogeneous solution.a. C6H14 and C10H20b. LiBr and C5H12c. N2O4 and NH4Cld. C6H14 and H2Oe. None of these pairs will form a homogeneous so

Problem

Choose the pair of substances that are most likely to form a homogeneous solution.

a. C6H14 and C10H20

b. LiBr and C5H12

c. N2O4 and NH4Cl

d. C6H14 and H2O

e. None of these pairs will form a homogeneous solution.

Solution

We’re being asked to determine which among the given pair of substances is most likely to form a homogenous solution.


Homogenous solution 

mixed together as evenly as possible
the components of the solution are indistinguishable


We’re going to use the theory “likes” dissolving “likes”  which states that the solvent can only completely dissolve the solute if they share similar polarity

Therefore, a pure solvent with similar polarity can successfully dissolve a solute to create a solution. 


Let take a look at each option given:

a. C6H14 and C10H20 

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