Ch.6 - Thermochemistry WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: A sample of gas occupies a volume of 51.1 mL. As it expands, it does 137.7 J of work on its surroundings at a constant pressure of 783 torr.What is the final volume of the gas?

Solution: A sample of gas occupies a volume of 51.1 mL. As it expands, it does 137.7 J of work on its surroundings at a constant pressure of 783 torr.What is the final volume of the gas?

Problem

A sample of gas occupies a volume of 51.1 mL. As it expands, it does 137.7 J of work on its surroundings at a constant pressure of 783 torr.

What is the final volume of the gas?

Solution

We’re being asked to calculate the final volume for a system if it expands from a volume of 51.1 mL against a constant pressure of 783 torr, doing 137.7 J of work in the process.


Recall that work (w) is given by:


w=-PΔV


where: 

P = pressure (in atm)

ΔV = Vfinal – Vinitial = change in volume (in L)


Also note that if work is:

• (+): work is done by the surroundings to the system (compression)

• (–): work is done by the system to the surroundings (expansion)


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