Problem: Calculate the equilibrium constant, K, for the following reaction at 25 °C.Fe3+(aq) +   B(s) + 6H2O (l) →   Fe(s) +   H 3BO3(s) +   3H3O+(aq)The balanced reduction half-reactions for the above equation and their respective standard reduction potential values (E°) are as follows:Fe3+(aq)   +    3e-  →  Fe(s)                                           Eo = -.04 VH3BO3(s) +   3H3O+(aq) +   3e- → B(s) +   6H2O(l)      Eo = -.8698 V

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Calculate the equilibrium constant, K, for the following reaction at 25 °C.

Fe3+(aq) +   B(s) + 6H2O (l) →   Fe(s) +   H 3BO3(s) +   3H3O+(aq)

The balanced reduction half-reactions for the above equation and their respective standard reduction potential values (E°) are as follows:

Fe3+(aq)   +    3e-  →  Fe(s)                                           Eo = -.04 V

H3BO3(s) +   3H3O+(aq) +   3e- → B(s) +   6H2O(l)      Eo = -.8698 V

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