Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: If Ka of HXO3 is > than Ka of HZO3 at 25°C, then it is most likely that:a. X is more electronegative than Zb. X exhibits a higher oxidation state than Zc. The H―X bond is weaker than the H―Z bondd. HXO3(aq) + ZO3(aq) ⇌ XO3(aq) + HZO3(aq) is reactant-favored at 25°Ce. Z is larger than X

Solution: If Ka of HXO3 is > than Ka of HZO3 at 25°C, then it is most likely that:a. X is more electronegative than Zb. X exhibits a higher oxidation state than Zc. The H―X bond is weaker than the H―Z bondd.

Problem

If Ka of HXO3 is > than Ka of HZO3 at 25°C, then it is most likely that:

a. X is more electronegative than Z

b. X exhibits a higher oxidation state than Z

c. The H―X bond is weaker than the H―Z bond

d. HXO3(aq) + ZO3(aq) ⇌ XO3(aq) + HZO3(aq) is reactant-favored at 25°C

e. Z is larger than X