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Solution: What concentration of the lead ion, Pb2+, must be exceeded to precipitate PbF2 from a solution that is 1.00x102 M in the fluoride ion, F? Ksp for lead(II) fluoride is 3.3x108.

Problem

What concentration of the lead ion, Pb2+, must be exceeded to precipitate PbF2 from a solution that is 1.00x10M in the fluoride ion, F? Ksp for lead(II) fluoride is 3.3x108.

Solution
  • By setting up an ICE table, we can get the concentration of Pb2+ 

  • Dissociation and the ICE table setup for PbF2 will appear as:

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