Chemistry Stoichiometry Solution: Using the following equation for the combustion of...

🤓 Based on our data, we think this question is relevant for Professor Jenkins' class at GGC.

Solution: Using the following equation for the combustion of octane, calculate the amount of moles of carbon dioxide formed from 100.0 g of octane. The molar mass of octane is 114.22 g/mol. The molar mass of carbon dioxide is 44.01 g/mol.a. 6.997 molesb. 8.000 molesc. 10.93 molesd. 18.18 molese. 14.00 moles

Problem

Using the following equation for the combustion of octane, calculate the amount of moles of carbon dioxide formed from 100.0 g of octane. The molar mass of octane is 114.22 g/mol. The molar mass of carbon dioxide is 44.01 g/mol.

a. 6.997 moles

b. 8.000 moles

c. 10.93 moles

d. 18.18 moles

e. 14.00 moles

Solution

Given:

• mass octane (C8H18) = 100 g
• molar mass octane (C8H18) = 114.22 g/mol
• molar mass carbon dioxide (CO2) = 44.01 g/mol  (extra information, not needed)

Solution BlurView Complete Written Solution