Consider the redox reaction:
PbO2(s) + Ba(s) + 4H+ (aq) → Pb+2 (aq) + Ba +2 (aq) + 2H2O(l)
At standard conditions ε° = 4.36 V (highly spontaneous). Suppose the voltage ε, is measured for the above reaction when the [H+] concentration is [H+] = 10 -7 M instead of [H+] = 1M.
How does ε compare to ε° (circle one):
ε > ε° ε < ε° ε = ε° Can't be determined
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