Problem: Calculate the pH of a 0.42 M NH 4Cl solution. (Kb for ammonia = 1.8 x 10 -5)

FREE Expert Solution

NH4Cl  → NH4+   +   Cl-

 NH4+   +   H2O    →   NH3   +   H3O+

Kb for ammonia = 1.8 x 10 -5


Calculate Ka

KaKb=KwKa=KwKbKa=1.0×10-141.8×10-5

Ka = 5.556x10-10


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Problem Details

Calculate the pH of a 0.42 M NH 4Cl solution. (Kb for ammonia = 1.8 x 10 -5)

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