Problem: a. How many moles of NH3 can be produced from 16.5 mol of H 2 and excess N2?b. How many grams of NH3 can be produced from 3.78 mol of N 2 and excess H2.c. How many grams of H 2 are needed to produce 11.05 g of NH3 ?d. How many molecules (not moles) of NH3 are produced from 2.92 × 10−4 g of H2?

🤓 Based on our data, we think this question is relevant for Professor Bindell's class at UCF.

FREE Expert Solution

The balanced reaction for this will appear as:

N2 (g) + 3 H2 (g) → 2 NH(g)

a. moles of NH3:

mol NH3 = 16.5 mol H2 (2 mol NH33 mol H2)

mol NH= 11 mol NH3

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Problem Details

a. How many moles of NH3 can be produced from 16.5 mol of H 2 and excess N2?

b. How many grams of NH3 can be produced from 3.78 mol of N 2 and excess H2.

c. How many grams of H 2 are needed to produce 11.05 g of NH3 ?

d. How many molecules (not moles) of NH3 are produced from 2.92 × 10−4 g of H2?

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Based on our data, we think this problem is relevant for Professor Bindell's class at UCF.