The dissociation of HF is as follows:
HF(aq) + H2O(l) ⇌ H3O+(aq) + F–(aq); Ka = 6.6 × 10–4
The Ka expression for HF is:
A. For 0.280 M:
Construct an ICE table.
Determine the pH of HF solution of each of the following concentrations.
a. 0.280 M
b. 5.00 x 10 -2 M
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