Problem: Determine the pH of HF solution of each of the following concentrations.a. 0.280 Mb. 5.00 x 10 -2 M

FREE Expert Solution

The dissociation of HF is as follows:


HF(aq) + H2O(l)  H3O+(aq) + F(aq); Ka = 6.6 × 10–4


The Ka expression for HF is:

Ka=productsreactant=[H3O+][F-][HF]



A. For  0.280 M:


Construct an ICE table.


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Problem Details

Determine the pH of HF solution of each of the following concentrations.

a. 0.280 M

b. 5.00 x 10 -2 M

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