bonding MOs → without an asterisk (e.g., σ1s)
antibonding MOs → those with an asterisk (e.g., σ1s*).
Step 1: The total number of valence electrons present in H2 is:
Group Valence Electrons
H 1A 2 × 1 e– = 2 e–
Total: 2 valence e–
Step 2: The molecular orbital diagram for H2 is:
Construct the molecular orbital diagram for H 2 and then identify the bond order.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Homonuclear Diatomic Molecules concept. If you need more Homonuclear Diatomic Molecules practice, you can also practice Homonuclear Diatomic Molecules practice problems.
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Based on our data, we think this problem is relevant for Professor Love's class at SDSU.