We’re being asked to rank the given solutions in order of increasing vapor pressure.
The vapor pressure of a solution is related to the intermolecular forces: a stronger IMF leads to lower vapor pressure. This means the solution with the lowest vapor pressure has the strongest IMF, and vice-versa.
We’re given the mass of solute and the volume of solvent (water).
Recall that a solution with higher solute concentration will have a stronger IMF, resulting in lower vapor pressure. Therefore, we need to calculate the osmolarity of each solution, which is given by:
where i = van’t Hoff factor.
Note that all the given volumes are in mL so we need to convert mL to L.
Rank the following solutions from lowest to highest vapor pressure. To rank items as equivalent, overlap them.
(1) 10.0 g of potassium acetate KC 2H3O2 in 100.0 mL of water
(2) 20.0 g of sucrose (C12H22O11) in 100.0 mL of water
(3) 20.0 g of glucose (C 6H12O6) in 100.0 mL of water
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the The Colligative Properties concept. You can view video lessons to learn The Colligative Properties. Or if you need more The Colligative Properties practice, you can also practice The Colligative Properties practice problems.
What is the difficulty of this problem?
Our tutors rated the difficulty ofRank the following solutions from lowest to highest vapor pr...as high difficulty.
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Our expert Chemistry tutor, Dasha took 11 minutes and 33 seconds to solve this problem. You can follow their steps in the video explanation above.
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Based on our data, we think this problem is relevant for Professor Brewer's class at UARK.