Problem: An electron in the n=7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 397 nm. What is the value of n for the level to which the electron relaxed?

FREE Expert Solution
95% (201 ratings)
FREE Expert Solution

We’re being asked to determine the value of n for the energy level to which the electron relaxed emitting light of 397 nm.


We’re going to use the Balmer Equation which relates wavelengths to a photon’s electronic transitions.

1λ=RZ21n2final-1n2initial

λ = wavelength, m
R = Rydberg constant = 1.097x107 m-1 
Z = atomic number of the element
ninitial = initial energy level
nfinal = final energy level


Calculate the final energy level (nfinal):

95% (201 ratings)
View Complete Written Solution
Problem Details

An electron in the n=7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 397 nm. What is the value of n for the level to which the electron relaxed?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Bohr and Balmer Equations concept. If you need more Bohr and Balmer Equations practice, you can also practice Bohr and Balmer Equations practice problems.

What is the difficulty of this problem?

Our tutors rated the difficulty ofAn electron in the n=7 level of the hydrogen atom relaxes to...as medium difficulty.

How long does this problem take to solve?

Our expert Chemistry tutor, Sabrina took 5 minutes and 44 seconds to solve this problem. You can follow their steps in the video explanation above.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Szulczewski's class at UA.