2C8H18 + 25O2 → 16CO2 + 18H2O
0.660 mol of octane is allowed to react with .780 mol of oxygen. Oxygen is the limiting reactant. After the reaction, how much octane is left?
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Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.
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Our tutors rated the difficulty of2C8H18 + 25O2 → 16CO2 + 18H2O0.660 mol of octane is allowed ...as low difficulty.
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Based on our data, we think this problem is relevant for Professor Tate's class at GENESEO.