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Solution: 2C8H18 + 25O2 → 16CO2 + 18H2O0.660 mol of octane is allowed to react with .780 mol of oxygen. Oxygen is the limiting reactant. After the reaction, how much octane is left?

Problem

2C8H18 + 25O2 → 16CO2 + 18H2O

0.660 mol of octane is allowed to react with .780 mol of oxygen. Oxygen is the limiting reactant. After the reaction, how much octane is left?

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