Learn how to solve problems like this one with our expert tutor.

Problem: 2C8H18 + 25O2 → 16CO2 + 18H2O0.660 mol of octane is allowed to react with .780 mol of oxygen. Oxygen is the limiting reactant. After the reaction, how much octane is left?

FREE Expert Solution
79% (412 ratings)
FREE Expert Solution
79% (412 ratings)
View Complete Written Solution
Problem Details

2C8H18 + 25O2 → 16CO2 + 18H2O

0.660 mol of octane is allowed to react with .780 mol of oxygen. Oxygen is the limiting reactant. After the reaction, how much octane is left?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.

What is the difficulty of this problem?

Our tutors rated the difficulty of2C8H18 + 25O2 → 16CO2 + 18H2O0.660 mol of octane is allowed ...as low difficulty.

How long does this problem take to solve?

Our expert Chemistry tutor, Dasha took 3 minutes and 29 seconds to solve this problem. You can follow their steps in the video explanation above.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Tate's class at GENESEO.