Problem: 2C8H18 + 25O2 → 16CO2 + 18H2O0.660 mol of octane is allowed to react with .780 mol of oxygen. Oxygen is the limiting reactant. After the reaction, how much octane is left?

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FREE Expert Solution
79% (412 ratings)
Problem Details

2C8H18 + 25O2 → 16CO2 + 18H2O

0.660 mol of octane is allowed to react with .780 mol of oxygen. Oxygen is the limiting reactant. After the reaction, how much octane is left?

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Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. You can view video lessons to learn Limiting Reagent Or if you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems .

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Based on our data, we think this problem is relevant for Professor Tate's class at GENESEO.