Problem: At 298 K, the Henry's law constant for oxygen is 0.00130 M/atm. Air is 21.0% oxygen.a) At 298 K, what is the solubility of oxygen in water exposed to air at 1.00 atm?  b) At 298 K, what is the solubility of oxygen in water exposed to air at 0.900 atm?  c) If atmospheric pressure suddenly changes from 1.00 atm to 0.900 atm at 298 K, how much oxygen will be released from 4.10 L of water in an unsealed container?

FREE Expert Solution
90% (435 ratings)
FREE Expert Solution

Recall that the solubility of a gas is given by Henry’s law:

where Sgas = solubility of the gas (in mol/L or M), kH = Henry’s law constant for the gas, Pgas = partial pressure of the gas.

90% (435 ratings)
Problem Details

At 298 K, the Henry's law constant for oxygen is 0.00130 M/atm. Air is 21.0% oxygen.

a) At 298 K, what is the solubility of oxygen in water exposed to air at 1.00 atm?

b) At 298 K, what is the solubility of oxygen in water exposed to air at 0.900 atm?

c) If atmospheric pressure suddenly changes from 1.00 atm to 0.900 atm at 298 K, how much oxygen will be released from 4.10 L of water in an unsealed container?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Intro to Henry's Law concept. You can view video lessons to learn Intro to Henry's Law Or if you need more Intro to Henry's Law practice, you can also practice Intro to Henry's Law practice problems .

What is the difficulty of this problem?

Our tutors rated the difficulty of At 298 K, the Henry's law constant for oxygen is 0.00130 M/a... as medium difficulty.

How long does this problem take to solve?

Our expert Chemistry tutor, Dasha took 6 minutes to solve this problem. You can follow their steps in the video explanation above.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Bell's class at PITT.