Problem: Ethanol has a heat of vaporization of 38.56 kJ/mol and a normal boiling point of 78.4 C.What is the vapor pressure of ethanol at 15°C?

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We’re being asked to determine the vapor pressure of ethanol at 15 ˚C, given the heat of vaporization and normal boiling point. For this problem, we can use the Clausius-Clapeyron Equation:



where:

P1 = vapor pressure at T1

P2 = vapor pressure at T2

ΔHvap = heat of vaporization (in J/mol)

R = gas constant (8.314 J/mol•K)

T1 and T2 = temperature (in K).


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Problem Details

Ethanol has a heat of vaporization of 38.56 kJ/mol and a normal boiling point of 78.4 C.

What is the vapor pressure of ethanol at 15°C?

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Our tutors have indicated that to solve this problem you will need to apply the Clausius-Clapeyron Equation concept. You can view video lessons to learn Clausius-Clapeyron Equation. Or if you need more Clausius-Clapeyron Equation practice, you can also practice Clausius-Clapeyron Equation practice problems.

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Based on our data, we think this problem is relevant for Professor Ratliff's class at USF.