🤓 Based on our data, we think this question is relevant for Professor Ratliff's class at USF.
Ethanol has a heat of vaporization of 38.56 kJ/mol and a normal boiling point of 78.4 C.
What is the vapor pressure of ethanol at 15°C?
We’re being asked to determine the vapor pressure of ethanol at 15 ˚C, given the heat of vaporization and normal boiling point. For this problem, we can use the Clausius-Clapeyron Equation:
P1 = vapor pressure at T1
P2 = vapor pressure at T2
ΔHvap = heat of vaporization (in J/mol)
R = gas constant (8.314 J/mol•K)
T1 and T2 = temperature (in K).