We’re being asked to calculate the molarity of formic acid if 25.00 mL of formic acid required 29.80 mL of 0.0567 M NaOH to reach the equivalence point. Recall that at the equivalence point of a titration:
Recall that moles = molarity × volume. This means:
Formic acid, Ka = 1.8x10 –4, is the principle component in the venom in stinging ants. What is the molarity of a formic acid solution if 25.00mL of formic acid solution requires 29.80mL of 0.0567M solution of sodium hydroxide to reach the equivalence point?
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Based on our data, we think this problem is relevant for Professor Kinyanjui's class at UNT.