Ch.16 - Aqueous Equilibrium See all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Formic acid, Ka = 1.8x10 –4, is the principle component in the venom in stinging ants. What is the molarity of a formic acid solution if 25.00mL of formic acid solution requires 29.80mL of 0.0567M solution of sodium hydroxide to reach the equivalence point? 0.0676M 0.0134M 0.0567M 0.0476M

Problem

Formic acid, Ka = 1.8x10 –4, is the principle component in the venom in stinging ants. What is the molarity of a formic acid solution if 25.00mL of formic acid solution requires 29.80mL of 0.0567M solution of sodium hydroxide to reach the equivalence point?

  1. 0.0676M
  2. 0.0134M
  3. 0.0567M
  4. 0.0476M