Problem: Formic acid, Ka = 1.8x10 –4, is the principle component in the venom in stinging ants. What is the molarity of a formic acid solution if 25.00mL of formic acid solution requires 29.80mL of 0.0567M solution of sodium hydroxide to reach the equivalence point?0.0676M0.0134M0.0567M0.0476M

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We’re being asked to calculate the molarity of formic acid if 25.00 mL of formic acid required 29.80 mL of 0.0567 M NaOH to reach the equivalence point. Recall that at the equivalence point of a titration:



Recall that moles = molarity × volume. This means:



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Problem Details

Formic acid, Ka = 1.8x10 –4, is the principle component in the venom in stinging ants. What is the molarity of a formic acid solution if 25.00mL of formic acid solution requires 29.80mL of 0.0567M solution of sodium hydroxide to reach the equivalence point?

  1. 0.0676M
  2. 0.0134M
  3. 0.0567M
  4. 0.0476M

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