Problem: Balance the following equation in acidic conditions. Phases are optional.C2O42- + MnO2 → Mn2+ + CO2

🤓 Based on our data, we think this question is relevant for Professor Wingrave's class at UD.

FREE Expert Solution

Step 1. Separate the whole reaction into half-reactions

C2O42- → CO2

MnO2 → Mn2+


Step 2. Balance the non-hydrogen and non-oxygen elements first

C2O42- → 2 CO2

MnO2 → Mn2+


Step 3. Balance oxygen by adding H2O to the side that needs oxygen (1 O: 1 H2O)

C2O42- → 2 CO2

MnO2 → Mn2+ + 2 H2O


Step 4. Balance hydrogen by adding H+ to the side that needs hydrogen (1 H: 1 H+)

C2O42- → 2 CO2

MnO2 + 4 H+ → Mn2+ + 2 H2O


Step 5. Balance the charges: add electrons to the more positive side (or less negative side)

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Problem Details

Balance the following equation in acidic conditions. Phases are optional.

C2O42- + MnO2 → Mn2+ + CO2

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What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Wingrave's class at UD.