Ch.3 - Chemical ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: One way to synthesize ethylamine (CH 3CH2NH2) is from the reaction of ammonia (NH3) with chloroethane (CH 3CH2Cl). (1)   NH3 + CH3CH2Cl → CH3CH2NH2 + HCl One problem with this synthesis route is tha

Problem

One way to synthesize ethylamine (CH 3CH2NH2) is from the reaction of ammonia (NH3) with chloroethane (CH 3CH2Cl).

(1)   NH3 + CH3CH2Cl → CH3CH2NH2 + HCl

One problem with this synthesis route is that the above reaction is not very selective, and ammonia may react with two chloroethane molecules to form diethylamine ( (CH3CH2)2NH ).

(2)   NH3 + 2 CH3CH2Cl → (CH3CH2)2NH + 2 HCl

A mixture of 0.475 mol NH3/mol, 0.475 mol CH3CH2Cl/mol and the remainder inerts is fed into a reactor. Within the reactor, the fractional conversion of CH3CH2Cl is 0.840 and the fractional yield of CH3CH2NH2 is 0.390. Assume a 100 mol basis for the feed stream, and calculate the number of moles of each component entering the reactor and leaving in the product stream.