# Problem: Aniline, C6H5NH2 is a weak base related to ammonia. It reacts with water as shown in the following equation.C6H5NH2 (aq) + H2O (l) → C6H5NH4+(aq) + OH- (aq)      Kb (aq) = 4.27 x 10 -10(a) Calculate ΔG° for the base ionization of aniline. (kJ/mol)(b) Calculate ΔG° for the base ionization of ammonia.(kJ/mol)

###### FREE Expert Solution

We’re asked to calculate ΔG° (kJ/mol) for the (a) base ionization of aniline and (b) base ionization of ammonia.

Recall that ΔG˚rxn and K are related to each other:

$\overline{){\mathbf{\Delta G}}{{\mathbf{°}}}_{{\mathbf{rxn}}}{\mathbf{=}}{\mathbf{-}}{\mathbf{RTlnK}}}$

where:

ΔG˚rxn = standard Gibbs free energy of the reaction

= 8 .314 J/mol • K (gas rate constant)

K = equilibrium constant

T = temperature in K (Kelvin)

Also, recall that Kb is the base dissociation constant and it is an equilibrium expression

To solve for ΔG˚ of aniline and ammonia,  we need to do these steps:

Step 1Determine base equilibrium constant, Kb for each base  .

Step 2: Calculate ΔG˚rxn

85% (142 ratings) ###### Problem Details

Aniline, C6H5NH2 is a weak base related to ammonia. It reacts with water as shown in the following equation.

C6H5NH(aq) + H2O (l) → C6H5NH4+(aq) + OH(aq)      K(aq) = 4.27 x 10 -10

(a) Calculate ΔG° for the base ionization of aniline. (kJ/mol)

(b) Calculate ΔG° for the base ionization of ammonia.(kJ/mol)