Atomic number = # of protons = # of electrons
Ag: atomic number = 47 → 47 protons & 47 electrons
Neutral Ag: 1s22s22p63s23p64s23d104p65s24d9
d orbitals → prefer to be half-filled or fully filled
move 1 electron from 5s to 4d
Neutral Ag: 1s22s22p63s23p64s23d104p65s14d10
Neutral Ag: 1s22s22p63s23p64s23d104p65s14d10
• Shorten the electron configuration by including a noble gas:
[1s22s22p63s23p64s23d104p6]6s2
Is the electron configuration for Ag+ [Kr]4d10?
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Based on our data, we think this problem is relevant for Professor Yousif's class at University of Detroit Mercy.