🤓 Based on our data, we think this question is relevant for Professor Billman's class at Abilene Christian University.
Aluminum sulfite reacts with sodium hydroxide to form sodium sulfite and aluminum hydroxide according to the following equation.
Al2(SO3)3 + 6 NaOH → 3 Na 2SO3 + 2 Al(OH)3
a) Determine the limiting reactant if 20.0 g of Al 2(SO3)3 reacts with 20.0 g of NaOH.
b) Determine the number of moles and mass of Al(OH) 3 produced.