# Problem: Aluminum sulfite reacts with sodium hydroxide to form sodium sulfite and aluminum hydroxide according to the following equation.Al2(SO3)3 + 6 NaOH → 3 Na 2SO3 + 2 Al(OH)3a) Determine the limiting reactant if 20.0 g of Al 2(SO3)3 reacts with 20.0 g of NaOH.     b) Determine the number of moles and mass of Al(OH) 3 produced.

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Aluminum sulfite reacts with sodium hydroxide to form sodium sulfite and aluminum hydroxide according to the following equation.

Al2(SO3)3 + 6 NaOH → 3 Na 2SO3 + 2 Al(OH)3

a) Determine the limiting reactant if 20.0 g of Al 2(SO3)3 reacts with 20.0 g of NaOH.

b) Determine the number of moles and mass of Al(OH) 3 produced.

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.

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Our tutors rated the difficulty ofAluminum sulfite reacts with sodium hydroxide to form sodium...as high difficulty.

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Based on our data, we think this problem is relevant for Professor Billman's class at Abilene Christian University.