Ch.14 - Chemical EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Ammonium Iodide dissociates reversibly to ammonia and hydrogen iodide:NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°CIf 150 g of ammonium iodide is placed into a 3.00 L vessel and heated to 400°C, calcula

Solution: Ammonium Iodide dissociates reversibly to ammonia and hydrogen iodide:NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°CIf 150 g of ammonium iodide is placed into a 3.00 L vessel and heated to 400°C, calcula

Problem

Ammonium Iodide dissociates reversibly to ammonia and hydrogen iodide:

NH4I(s) ⇋ NH3(g) + HI(g)

Kp = 0.215 at 400°C

If 150 g of ammonium iodide is placed into a 3.00 L vessel and heated to 400°C, calculate the partial pressure of ammonia when equilibrium is reached. Hint: Ammonium Iodide is a solid, is it used in the equilibrium calculation? 

Solution
  • We can get the partial pressure of ammonia by setting up an ICE table using the Kp given

  • Recall that solids don't play a role when we are dealing with pressure at equilibrium

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