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We can get the partial pressure of ammonia by setting up an ICE table using the Kp given
Recall that solids don't play a role when we are dealing with pressure at equilibrium
Ammonium Iodide dissociates reversibly to ammonia and hydrogen iodide:
NH4I(s) ⇋ NH3(g) + HI(g)
Kp = 0.215 at 400°C
If 150 g of ammonium iodide is placed into a 3.00 L vessel and heated to 400°C, calculate the partial pressure of ammonia when equilibrium is reached. Hint: Ammonium Iodide is a solid, is it used in the equilibrium calculation?
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