Since Xe is less electronegative than O, Xe will appear as our central atom
Valence electron for O is 6 while Xe is 8. Total will appear as: 32 valence electrons (8+ 6*4 = 32)
a) Draw the lewis structure, optimizing formal charges.
b) Identify the electron pair geometry for each center.
c) Identify the molecular geometry for each center.
d) Identify the hybridization for each center.
e) Label all sigma bonds.
f) Label all pi bonds. note the orbitals involved in the pibond.
g) Draw the hybridization diagram.
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