We’re being asked to draw a Lewis structure for AlCl3. We first need to determine the total number of valence electrons present in the molecule:
Group Valence Electrons
Al 3A 1 × 3 e– = 3 e–
Cl 7A 3 × 7 e– = 21 e–
Total: 24 valence e–
Draw the Lewis dot structure for AlCl 3.
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