• molar mass ethylene glycol = 62.07 g/mol
• molar mass ethanol = 46.07 g/mol
• mass ethanol = 1.00 kg
• vapor pressure pure ethanol = 100 torr
• vapor pressure of solution → vapor pressure solvent reduced by 10 torr
Calculate the mass of ethylene glycol (C2H6O2, molar mass = 62.07 g/mol) that must be added to 1.00 kg of ethanol (C2H5OH, molar mass = 46.07 g/mol) to reduce its vapor pressure by 10.0 torr at 35 °C. The vapor pressure of pure ethanol at 35 °C is 100 torr.
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