We’re being asked to determine the formation constant of Cu(NH3)42+.
We’re given the following reaction and equilibrium constant:
Cu(OH)2(s) + 4 NH3(aq) ⇌ Cu(NH3)42+(aq) + 2 OH–(aq); Keq = 4.0 × 10–7
The Keq expression for this reaction is:
Note that solids and liquids are not included in the equilibrium expression and that each concentration is raised by the stoichiometric coefficient: [NH3] is raised to 4, [Cu(NH3)42+] is raised to 1, and [OH–] is raised to 2.
Copper(II) hydroxide, Cu(OH)2, has Ksp = 2.2 x 10 -20. For the reaction below, Keq = 4.0 x 10-7. What is Kf for Cu(NH3)42+?
Cu(OH)2(s) + 4 NH3(aq) ⇋ Cu(NH3)42+(aq) + 2 OH -(aq)
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