Use the following information to calculate the ΔH° lattice of MgF2:
Mg(s) → Mg(g) ΔH° =148 kJ
F2(g) → 2F(g) ΔH° =159 kJ
Mg(g) → Mg+ (g)+e- ΔH° =738 kJ
Mg+(g) → Mg2+ (g)+e- ΔH° =1450 kJ
F(g)+e- → F-(g) ΔH° =-328 kJ
Mg(s) +F2(g) → MgF2 (s) ΔH° =-1123 kJ
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