Use the standard enthalpies of formation in the table
CrO42- (aq) = -881.2
Cr2O72-(aq) = -1490.3
H+ (aq) = 0
H2O (l) = -285.8
to calculate ΔH for this reaction:
2CrO42- (aq) + 2H+(aq) → Cr2O72-(aq) + H2O (l)
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