Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Acetic acid, HC2H3O2, is a weak acid. The following is the equilibrium equation for its reaction with water: HC2H3O2 (aq) + H2O (l) ⇌ H 3O+ (aq) + C2H3O2-(aq)     Ka = 1.8 x 10-5 What is the pOH of

Problem

Acetic acid, HC2H3O2, is a weak acid. The following is the equilibrium equation for its reaction with water:

HC2H3O(aq) + H2O (l) ⇌ H 3O(aq) + C2H3O2-(aq)     Ka = 1.8 x 10-5

What is the pOH of a 4.27 M HC 2H3O2 solution?

Note: Assume that the ionization of the acid is small enough in comparison to its starting concentration that the concentration of unionized acid is almost as large at equilibrium as it was originally. This will allow you to avoid having to solve the quadratic formula when doing your ICE table calculation.

a. 2.06

b. 3.98

c. 5.16

d. 10.02

e. 11.94