The Lewis structures for this set of compounds are similar since we are using C as central atom which will follow a tetrahedral structure
We have to analyze each of the atoms attached to C to determine which will contribute more to the polarity of the molecule
Trend for electronegativity is increasing from bottom to top. Therefore F > Cl > Br will be our guide
For the polarity of the molecules, due to a big difference in polarity with H and halogens, this combination will appear as our most polar combination
In this case, we have CH2Br2, CH2F2 and CH2Cl2
Rank the following molecules from the least polar to the most polar:
CH2Br2, CF2Cl2, CH2F2, CH2Cl2, CBr4, CF2Br2.
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