Calculate the amount, in mL, of 0.0168 M Ca(OH) 2 that would be required to completely react with 25.38 mL of 0.0784 M HClO3.
A) 5.44 mL
B) 59.22 mL
C) 236.88 mL
D) 2.72 mL
E) 10.88 mL
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