Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Balance the following equation in basic conditions. Phases are optional.CoCl2 + Na2O2 → Co(OH)3 + Cl- + Na+(redox and oxidation reactions) 

Solution: Balance the following equation in basic conditions. Phases are optional.CoCl2 + Na2O2 → Co(OH)3 + Cl- + Na+(redox and oxidation reactions) 

Problem

Balance the following equation in basic conditions. Phases are optional.

CoCl+ Na2O→ Co(OH)+ Cl- + Na+

(redox and oxidation reactions)

 

Solution

First, we must split the reaction into two half-reactions. We do this based on their elements.

$CoCl_2 → Co(OH)_3 + Cl^- \qquad and \qquad Na_2O_2 → Na^+$

The next step is to balance elements different than oxygen and hydrogen first.

$CoCl_2 → Co(OH)_3 + 2\ Cl^- \qquad and \qquad Na_2O_2 → 2\ Na^+$

Next, we balance out oxygens by adding waters or $H_2O$.

$CoCl_2 → Co(OH)_3 + 2\ Cl- \qquad and \qquad Na_2O_2 → 2Na^+ $

$+3\ H_2O \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \ \ +2\ H_2O$

Next, we balance out hydrogens by adding H+.

$CoCl_2 → Co(OH)_3 + 2\ Cl- \qquad and \qquad Na_2O_2 → 2Na^+ $

$+3\ H_2O \qquad \qquad \quad+ 3\ H^{+} \qquad \qquad \quad+ 4\ H^+ \qquad +2\ H_2O$

Next, we balance out the overall charge. For the first reaction:

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