Ch.11 - Liquids, Solids & Intermolecular ForcesWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Which solids will melt under applied pressure? Check all that apply.

Solution: Which solids will melt under applied pressure? Check all that apply.

Problem

Which solids will melt under applied pressure? Check all that apply.

Solution

$\textbf{Start with Solid A:}$

Calculate the heat of fusion as follows:

$ln\frac{P_2}{P_1} = \frac{\Delta H_{fus}}{R}(\frac{1}{T_1}-\frac{1}{T_2})$

$ln\frac{1\ atm}{0.91 \ atm} = \frac{\Delta H_{fus}}{8.314\ J/mol-K}(\frac{1}{124.+273.15K}-\frac{1}{108+273.15K})$

$0.0943=\Delta H_{fus} \times (-1.271\times 10^{-5})$

$\Delta H_{fus} = -7420\ J/mol$

$\textbf{Then, Solid B:}$

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