Ch.16 - Aqueous Equilibrium WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: C2D3 has a solubility product constant of 9.14 x 10 -9. What is the molar solubilty of C2D3?

Problem

C2D3 has a solubility product constant of 9.14 x 10 -9. What is the molar solubilty of C2D3?

Solution

$C_2D_3$ is going to be a solid, meaning it will dissociate completely as follows:

$C_2D_{3(s)} \rightarrow 2\ C^{3+}_{(aq)} + 3\ D^{2-} _{(aq)}$

To find the molar solubility (x), me must assume:

$C_2D_3 \rightarrow 2X + 3X$

The equilibrium expression for Ksp is:

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