Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Complete this table of values for four aqueous solutions at 25°c 

Solution: Complete this table of values for four aqueous solutions at 25°c 

Problem

Complete this table of values for four aqueous solutions at 25°c

 

Solution

pH  of a solution is found by: pH = -log[H+]

pOH of a solution is found by: pOH = -log[OH-]

The relationship between pH and pOH is: pH + pOH = 14

[H+] [OH-] = 1.0 x 10-14

For solution A:

The concentration of [H+ given is 7.6x10-12M

To find pH:

pH = -log[H+]          pH = -log [7.6x10-12]          pH = 11.12

View the complete written solution...