Ch.15 - Acid and Base EquilibriumSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: You are given two solutions: 0.50 M HCl (aq) and 0.50 M Ca(OH) 2 (aq). What is the [H+] in the HCl solution? What is the [OH -] in the Ca(OH)2 solution? (The solutions are NOT mixed together). a) [H+] : 0.50 M; [OH -] : 0.50 M b) [H+] : 0.25 M; [OH -] : 1.0 M c) [H+] : 0.50 M; [OH -] : 0.25 M d) [H+] : 0.25 M; [OH -] : 0.25 M e) [H+] : 0.50 M; [OH -] : 1.0 M

Problem

You are given two solutions: 0.50 M HCl (aq) and 0.50 M Ca(OH) (aq). What is the [H+] in the HCl solution? What is the [OH -] in the Ca(OH)2 solution? (The solutions are NOT mixed together).

a) [H+] : 0.50 M; [OH -] : 0.50 M

b) [H+] : 0.25 M; [OH -] : 1.0 M

c) [H+] : 0.50 M; [OH -] : 0.25 M

d) [H+] : 0.25 M; [OH -] : 0.25 M

e) [H+] : 0.50 M; [OH -] : 1.0 M