Ch. 17 - Chemical ThermodynamicsSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: In the gas phase, methyl isocyanate (CH 3NC) isomerizes to acetonitrile (CH 3CN), H3C−N≡C (g) ⇄ H3C−C≡N (g) with ΔHo = –89.5 kJ/mol and ΔGo = –73.8 kJ/mol at 25oC. What is the equilibrium constant, Kp, for this reaction at 100oC, assuming that the enthalpy and entropy of reaction are independent of temperature. a) 4.62 x 10 ‐11 b) 1.68 x 10 ‐10 c) 5.96 x 109 d) 5.36 x 109 e) 8.64 x 1012

Problem

In the gas phase, methyl isocyanate (CH 3NC) isomerizes to acetonitrile (CH 3CN),

H3C−N≡C (g) ⇄ H3C−C≡N (g)

with ΔHo = –89.5 kJ/mol and ΔGo = –73.8 kJ/mol at 25oC. What is the equilibrium constant, Kp, for this reaction at 100oC, assuming that the enthalpy and entropy of reaction are independent of temperature.

a) 4.62 x 10 ‐11

b) 1.68 x 10 ‐10

c) 5.96 x 109

d) 5.36 x 109

e) 8.64 x 1012